Jacksonville is keeping one of its own free agents, re-signing defensive end Dawuane Smoot.
NFL Media’s Ian Rapoport reports the deal is for two years and worth $14 million.
Smoot was a Jaguars third-round pick back in 2017. He appeared in all 16 games in 2020, starting seven, and recorded 5.5 sacks, 17 quarterback hits, and five tackles for loss. He also forced a pair of fumbles. He played 59 percent of the club’s defensive snaps in 2020.
Overall, Smoot has 11.5 career sacks — recording 6.0 in 2019.